Compare vocabularies with set operations

compare_convo(vocab1, vocab2, fx = c("setdiff", "intersect", "union"))

Arguments

vocab1	Vocabulary list (or `convo` object). In the case of validating a new vocabulary against an existing one, this argument should take the new vocabulary.
vocab2	Vocabulary list (or `convo` object). In the case of validating a new vocabulary against an existing one, this argument should take the existing vocabulary.
fx	Character string describing comparison function. `setdiff` returns those in `vocab1` not in `vocab2`; `intersect` returns those in both `vocab1` and `vocab2`; `union` returns all elements in either

Value

List (of class convomin) of mismatches

Examples

v1 <- list(letters[1:3], letters[4:6], letters[7:9])
v2 <- list(letters[(1:3)+1], letters[(4:6)-2], letters[7])
compare_convo(v1, v2, "setdiff")
#> Level 1
#> - a
#> Level 2
#> - e
#> - f
#> Level 3
#> - h
#> - i
compare_convo(v1, v2, "union")
#> Level 1
#> - b
#> - a
#> - c
#> - d
#> Level 2
#> - b
#> - d
#> - e
#> - f
#> - c
#> Level 3
#> - g
#> - h
#> - i
compare_convo(v1, v2, "intersect")
#> Level 1
#> - b
#> - c
#> Level 2
#> - d
#> Level 3
#> - g